So, the Wiki has listed the ways that a player can rank up Syndicates (as in: Gain points) at the same time (for the sake of this thread, when I mean "at the same time", I mean, "using the same method for ranking up Syndicates for some appreciable length of time, and working for at least two Syndicates".). Now, as some players are wondering if one could rank up all six Syndicates at the same time, the short answer is: No.
The long answer is:
Version 1:
Yes, I know the proof has a bit of hand-waving, but for the most part, it looks solid. This only applies to Rank 0, as with higher ranks come higher Syndicate point capacity, meaning that this proof starts falling apart due to being able to store more points as a buffer.
EDIT: Re-reading the proof again, I made a small mistake, and that is saying the proof does apply for Rank 0 only. It can be applied to all combinations of Syndicate ranks, as this proof calculates the change of Syndicate points with respect to percentage of time spent in a Syndicate in a particular method of gaining Syndicate points (e.g.: If I spend 100% of my time in RV, then I used 100% of my time to gain 100% of RV Syndicate points, converted from Affinity, and 100% of my time to gain -100% of AH Syndicate points, converted from Affinity). That means my conclusion is actually the implication from the result that one cannot gain positive Syndicate points for all Syndicates at the same time.
But this assumes that the percentage of time spent in a Syndicate will produce a proportional amount of Affinity.
2nd EDIT: SM, RV, NL, PS, CS, AH should be ≥ 0 rather than > 0.
Question
Renegade343
So, the Wiki has listed the ways that a player can rank up Syndicates (as in: Gain points) at the same time (for the sake of this thread, when I mean "at the same time", I mean, "using the same method for ranking up Syndicates for some appreciable length of time, and working for at least two Syndicates".). Now, as some players are wondering if one could rank up all six Syndicates at the same time, the short answer is: No.
The long answer is:
Version 1:
Version 2 (the improved/more clearer version):
Link to comment
Share on other sites
31 answers to this question
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now